# CAT Online Test Series 5 | Free CAT Quiz Series 5 | CAT Free Mock Test

## CAT Online Test Series 5 | Free CAT Quiz Series 5 | CAT Free Mock Test

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**CAT Online Test Series 5 | Free CAT Quiz Series 5 | CAT Free Mock Test.** Common Admission Test (CAT) is one of the most challenging and competitive MBA entrance test in our country. Check your level of preparation for *CAT* with free All India *Mock test* 2018. CAT Exam Online Test 2018, CAT Free Mock Test Exam 2018. CAT Exam Free Online Quiz 2018, CAT Full Online Mock Test **Series 5th** in English. CAT Online Test for All Subjects, CAT Free Mock Test Series in English. CAT Free Mock Test **Series 5.** CAT English Language Online Test in English **Series 5th**. Here we are providing** CAT Full Mock Test Paper in English. CAT **Mock Test **Series 5th** 2018. Now Test your self for CAT Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?

Correct(A + B) – (B + C) = 12

A – C = 12Incorrect(A + B) – (B + C) = 12

A – C = 12 - Question 2 of 50
##### 2. Question

At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?

CorrectA = 20000(11/10)

^{3}

= 26620

= 20000

———-

6620IncorrectA = 20000(11/10)

^{3}

= 26620

= 20000

———-

6620 - Question 3 of 50
##### 3. Question

Ajay and Vijay have some marbles with them. Ajay told Vijay “if you give me ‘x’ marbles, both of us will have equal number of marbles”. Vijay then told Ajay “if you give me twice as many marbles, I will have 30 more marbles than you would”. Find ‘x’?

CorrectIf Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.

V – x = A + x — (1)

If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.

V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)

From (1) we have V – A = 2x

Substituting V – A = 2x in (2)

6x = 30 => x = 5.IncorrectIf Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.

V – x = A + x — (1)

If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.

V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)

From (1) we have V – A = 2x

Substituting V – A = 2x in (2)

6x = 30 => x = 5. - Question 4 of 50
##### 4. Question

Which one of the following is the least number of four digits divisible by 71?

Correct1000/71 = 14 6/71

1000 + 71 – 6 = 1065Incorrect1000/71 = 14 6/71

1000 + 71 – 6 = 1065 - Question 5 of 50
##### 5. Question

If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:

CorrectLet C.P. of each pen be Re. 1.

Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.

Gain % = 4/8 * 100 = 50%IncorrectLet C.P. of each pen be Re. 1.

Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.

Gain % = 4/8 * 100 = 50% - Question 6 of 50
##### 6. Question

How many figures are required to number the pages the pages of a book containing 365 pages?

Correct1 to 9 = 9 * 1 = 9

10 to 99 = 90 * 2 = 180

100 to 365 = 266 * 3 = 798

= ———–

= 987Incorrect1 to 9 = 9 * 1 = 9

10 to 99 = 90 * 2 = 180

100 to 365 = 266 * 3 = 798

= ———–

= 987 - Question 7 of 50
##### 7. Question

A cylinder and a cone have a same height and same radius of the base. The ratio between the volumes of the cylinder and cone is?

CorrectIncorrect - Question 8 of 50
##### 8. Question

Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?

CorrectKim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3

Kim’s share = 2/5 * 150 = Rs. 60IncorrectKim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3

Kim’s share = 2/5 * 150 = Rs. 60 - Question 9 of 50
##### 9. Question

The least number of four digits which is divisible by 15, 25, 40 and 75 is:

CorrectGreatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600IncorrectGreatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.

On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600 - Question 10 of 50
##### 10. Question

The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?

Correct400*(90/100)*(95/100) = 342

Incorrect400*(90/100)*(95/100) = 342

- Question 11 of 50
##### 11. Question

Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?

Correct2: 5: 13

2x 5x 13x

15 7.5 2.5

30x + 37.5x + 32.5x = 100x/20x

Average = 5Incorrect2: 5: 13

2x 5x 13x

15 7.5 2.5

30x + 37.5x + 32.5x = 100x/20x

Average = 5 - Question 12 of 50
##### 12. Question

A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 350 m long platform?

CorrectLet the length of the train be x m.

When a train crosses an electric pole, the distance covered is its own length.

So, x = 12 * 36 * 5 /18 m = 120 m.

Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min.IncorrectLet the length of the train be x m.

When a train crosses an electric pole, the distance covered is its own length.

So, x = 12 * 36 * 5 /18 m = 120 m.

Time taken to cross the platform = (120 +350)/ 36 * 5/18 = 47 min. - Question 13 of 50
##### 13. Question

9 men and 12 boys finish a job in 12 days, 12 men and 12 boys finish it in 10 days. 10 men and 10 boys shall finish it in how many days?

Correct9M + 12B —– 12 days

12M + 12B ——- 10 days

10M + 10B ——-?

108M + 144B = 120M +120B

24B = 12M => 1M = 2B

18B + 12B = 30B —- 12 days

20B + 10B = 30B —–? => 12 daysIncorrect9M + 12B —– 12 days

12M + 12B ——- 10 days

10M + 10B ——-?

108M + 144B = 120M +120B

24B = 12M => 1M = 2B

18B + 12B = 30B —- 12 days

20B + 10B = 30B —–? => 12 days - Question 14 of 50
##### 14. Question

22004 – 29303 + 101299 – 59532 = ?

Correct22004 – 29303 + 101299 – 59532

123303 – 888.35 = 34468 = 34500Incorrect22004 – 29303 + 101299 – 59532

123303 – 888.35 = 34468 = 34500 - Question 15 of 50
##### 15. Question

A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 6 runs. His new average is:

CorrectLet average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs.IncorrectLet average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs. - Question 16 of 50
##### 16. Question

A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?

Correct900 —- 180

100 —- ? => 20%Incorrect900 —- 180

100 —- ? => 20% - Question 17 of 50
##### 17. Question

One root of the quadratic equation x

^{2}– 12x + a = 0, is thrice the other. Find the value of a?CorrectLet the roots of the quadratic equation be x and 3x.

Sum of roots = -(-12) = 12

a + 3a = 4a = 12 => a = 3

Product of the roots = 3a^{2}= 3(3)^{2}= 27.IncorrectLet the roots of the quadratic equation be x and 3x.

Sum of roots = -(-12) = 12

a + 3a = 4a = 12 => a = 3

Product of the roots = 3a^{2}= 3(3)^{2}= 27. - Question 18 of 50
##### 18. Question

The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?

Correct3x + 5x + 7x = 45

x =3

3x = 9Incorrect3x + 5x + 7x = 45

x =3

3x = 9 - Question 19 of 50
##### 19. Question

Rs.590 is divided amongst A, B, C so that 5 times A’s share, six times B’s share and eight times C’s share are all equal. Find C’s share?

CorrectA+B+C = 590

5A = 6B = 8C = x

A:B:C = 1/5:1/6:1/8

= 24:20:15

15/59 * 590 = Rs.150IncorrectA+B+C = 590

5A = 6B = 8C = x

A:B:C = 1/5:1/6:1/8

= 24:20:15

15/59 * 590 = Rs.150 - Question 20 of 50
##### 20. Question

Find the one which does not belong to that group ?

CorrectTiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.

IncorrectTiruvanantapuram, Hyderabad, Bangalore and Bhubaneswar are state capitals, while Calicut is not a state capital.

- Question 21 of 50
##### 21. Question

If one-third of one fourth of a number is 15, then three-tenth of that number is:

CorrectLet the number be x. Then,

1/3 of 1/4 of x = 15

x = 15 * 12 = 180

So, required number = (3/10 * 180) = 54.IncorrectLet the number be x. Then,

1/3 of 1/4 of x = 15

x = 15 * 12 = 180

So, required number = (3/10 * 180) = 54. - Question 22 of 50
##### 22. Question

A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?

CorrectLength of the train be ‘X’

X + 120/15 = X + 180/18

6X + 720 = 5X + 900

X = 180mIncorrectLength of the train be ‘X’

X + 120/15 = X + 180/18

6X + 720 = 5X + 900

X = 180m - Question 23 of 50
##### 23. Question

A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?

CorrectSpeed = 54 * 5/18 = 15 m/sec.

Length of the train = 15 * 20 = 300 m.

Let the length of the platform be x m . Then,

(x + 300)/36 = 15 => x = 240 m.IncorrectSpeed = 54 * 5/18 = 15 m/sec.

Length of the train = 15 * 20 = 300 m.

Let the length of the platform be x m . Then,

(x + 300)/36 = 15 => x = 240 m. - Question 24 of 50
##### 24. Question

How many numbers up to 200 are divisible by 2 and 3 both?

Correct200/6 = 33 2/6 => 33 Numbers

Incorrect200/6 = 33 2/6 => 33 Numbers

- Question 25 of 50
##### 25. Question

A garrison of 400 men had a provision for 31 days. After 28 days 280 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?

Correct400 — 31

400 — 3

120 — ?

400*3 = 120*x => x =10 daysIncorrect400 — 31

400 — 3

120 — ?

400*3 = 120*x => x =10 days - Question 26 of 50
##### 26. Question

The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:

CorrectLet the numbers be 13a and 13b.

Then, 13a * 13b = 2028 => ab = 12.

Now, co-primes with product 12 are (1, 12) and (3, 4).

So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).

Clearly, there are 2 such pairs.IncorrectLet the numbers be 13a and 13b.

Then, 13a * 13b = 2028 => ab = 12.

Now, co-primes with product 12 are (1, 12) and (3, 4).

So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).

Clearly, there are 2 such pairs. - Question 27 of 50
##### 27. Question

Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:

CorrectLet the present ages of the father and son be 2x and x years respectively.

Then, (2x – 18) = 3(x – 18) => x = 36

Required sum = (2x + x) = 108 years.IncorrectLet the present ages of the father and son be 2x and x years respectively.

Then, (2x – 18) = 3(x – 18) => x = 36

Required sum = (2x + x) = 108 years. - Question 28 of 50
##### 28. Question

A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?

CorrectPrincipal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)

= [882/(1 + 5/100) + 882/(1 + 5/100)^{2}]

= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640.IncorrectPrincipal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)

= [882/(1 + 5/100) + 882/(1 + 5/100)^{2}]

= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640. - Question 29 of 50
##### 29. Question

On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:

CorrectBy hit and trail, we find that

47619 * 7 = 333333.

7) 333333 (47619

333333

—————-

0IncorrectBy hit and trail, we find that

47619 * 7 = 333333.

7) 333333 (47619

333333

—————-

0 - Question 30 of 50
##### 30. Question

In how many years will a sum of money doubles itself at 5% per annum on simple interest?

CorrectP = (P*5*R)/100

R = 20%IncorrectP = (P*5*R)/100

R = 20% - Question 31 of 50
##### 31. Question

A, B and C invests Rs.2000, Rs.3000 and Rs.4000 in a business. After one year A removed his money; B and C continued the business for one more year. If the net profit after 2 years be Rs.3200, then A’s share in the profit is?

Correct2*12 : 3*12 : 4*24

1: 3: 4

1/8 * 3200 = 400Incorrect2*12 : 3*12 : 4*24

1: 3: 4

1/8 * 3200 = 400 - Question 32 of 50
##### 32. Question

Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?

Correct1/12 + 1/15 – 1/x = 1/15

x = 12

12 * 45 = 540Incorrect1/12 + 1/15 – 1/x = 1/15

x = 12

12 * 45 = 540 - Question 33 of 50
##### 33. Question

If x = 3 – √7, then find the value of x + 1/x.

Correctx = 3 – √7

1/x = 1/(3 – √7) = (3 + √7)/(3 – √7)(3 + √7)

= (3 + √7)/2 => x + 1/x (9 – √7)/2Incorrectx = 3 – √7

1/x = 1/(3 – √7) = (3 + √7)/(3 – √7)(3 + √7)

= (3 + √7)/2 => x + 1/x (9 – √7)/2 - Question 34 of 50
##### 34. Question

Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?

CorrectLet the three consecutive odd integers be x, x + 2 and x + 4 respectively.

x + 4 + x + 2 = x + 13 => x = 7

Hence three consecutive odd integers are 7, 9 and 11.IncorrectLet the three consecutive odd integers be x, x + 2 and x + 4 respectively.

x + 4 + x + 2 = x + 13 => x = 7

Hence three consecutive odd integers are 7, 9 and 11. - Question 35 of 50
##### 35. Question

The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?

CorrectSI = 20 + 20

CI = 20 + 21

20 —- 1

100 —- ? => 5%IncorrectSI = 20 + 20

CI = 20 + 21

20 —- 1

100 —- ? => 5% - Question 36 of 50
##### 36. Question

A gardener wants to plant trees in his garden in rows in such a way that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42 if there are 12 more rows find the number of trees in each row?

CorrectRequired number of trees

= 24/36 * 42 = 28.IncorrectRequired number of trees

= 24/36 * 42 = 28. - Question 37 of 50
##### 37. Question

The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is:

CorrectRequired fraction = L.C.M of 6/7, 5/14, 10/21

= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7IncorrectRequired fraction = L.C.M of 6/7, 5/14, 10/21

= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7 - Question 38 of 50
##### 38. Question

Two trains are moving at 50 kmph and 70 kmph in opposite directions. Their lengths are 150 m and 100 m respectively. The time they will take to pass each other completely is?

Correct70 + 50 = 120 * 5/18 = 100/3 mps

D = 150 + 100 = 250 m

T = 250 * 3/100 = 15/2 = 7 ½ secIncorrect70 + 50 = 120 * 5/18 = 100/3 mps

D = 150 + 100 = 250 m

T = 250 * 3/100 = 15/2 = 7 ½ sec - Question 39 of 50
##### 39. Question

Find the one which does not belong to that group ?

CorrectAll are organs of our body which are in pairs except fingers.

IncorrectAll are organs of our body which are in pairs except fingers.

- Question 40 of 50
##### 40. Question

A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

CorrectHCF of 1189, 1073 = 29

1073/29 = 37IncorrectHCF of 1189, 1073 = 29

1073/29 = 37 - Question 41 of 50
##### 41. Question

7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/6 equals -.

Correct7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16

= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32

= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224

= 12 + 25/224 = 12 25/224Incorrect7 + 5 – (3/2 * 1/4) of 2/7 + 7/2 * 1/16

= 7 + 5 – (3/2 * 1/4) * 2/7 + 7/2 * 1/16 = 7 + 5 – 3/28 + 7/32

= 12 + 3/28 + 7/32 = 12 + (7 * 7 – 3 * 8)/224

= 12 + 25/224 = 12 25/224 - Question 42 of 50
##### 42. Question

Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is?

CorrectLet us name the trains A and B.

Then, (A’s speed) : (B’s speed)

= √b : √a = √16 : √9 = 4:3IncorrectLet us name the trains A and B.

Then, (A’s speed) : (B’s speed)

= √b : √a = √16 : √9 = 4:3 - Question 43 of 50
##### 43. Question

There are 18 stations between Hyderabad and Bangalore. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station?

CorrectThe total number of stations = 20

From 20 stations we have to choose any two stations and the direction of travel (i.e., Hyderabad to Bangalore is different from Bangalore to Hyderabad) in ²⁰P₂ ways.

²⁰P₂ = 20 * 19 = 380.IncorrectThe total number of stations = 20

From 20 stations we have to choose any two stations and the direction of travel (i.e., Hyderabad to Bangalore is different from Bangalore to Hyderabad) in ²⁰P₂ ways.

²⁰P₂ = 20 * 19 = 380. - Question 44 of 50
##### 44. Question

Find the number of factors of 300 excluding 1 and itself.

Correct300 = 4.75 = 4.25.3 = 2

^{2}.5^{2}.3^{1}

Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.

There are 16 factors of 300 excluding 1 and itself.Incorrect300 = 4.75 = 4.25.3 = 2

^{2}.5^{2}.3^{1}

Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.

There are 16 factors of 300 excluding 1 and itself. - Question 45 of 50
##### 45. Question

An article is bought for Rs.600 and sold for Rs.500, find the loss percent?

Correct600 —- 100

100 —- ? => 16 2/3%Incorrect600 —- 100

100 —- ? => 16 2/3% - Question 46 of 50
##### 46. Question

Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.

Correctn(S) = 20

n(Even no) = 10 = n(E)

n(Prime no) = 8 = n(P)

P(EᴜP) = 10/20 + 8/20 – 1/20 = 17/20Incorrectn(S) = 20

n(Even no) = 10 = n(E)

n(Prime no) = 8 = n(P)

P(EᴜP) = 10/20 + 8/20 – 1/20 = 17/20 - Question 47 of 50
##### 47. Question

By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?

CorrectCP + CP/8 = 45000

CP = 40000

SP = 40000*(95/100) = 38000IncorrectCP + CP/8 = 45000

CP = 40000

SP = 40000*(95/100) = 38000 - Question 48 of 50
##### 48. Question

How many three letter words are formed using the letters of the word TIME?

CorrectThe number of letters in the given word is four.

The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24.IncorrectThe number of letters in the given word is four.

The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24. - Question 49 of 50
##### 49. Question

If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?

Correcta/d = (3/4)*(7/9)*(5/7) => 5/12

Incorrecta/d = (3/4)*(7/9)*(5/7) => 5/12

- Question 50 of 50
##### 50. Question

A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?

CorrectC = 1/5 – 1/6 = 1/30 => 30 days

IncorrectC = 1/5 – 1/6 = 1/30 => 30 days