# RRB NTPC Online Test in English Series 2, RRB NTPC Mock Test Series 2

## RRB NTPC Online Test in English Series 2, RRB NTPC Mock Test

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RRB NTPC Online Test in English – Series 2, RRB NTPC Free Online Test Series 2. RRB Exam Online Test 2018, RRB NTPC Free Mock Test Exam 2018.**RRB NTPC Full Online Mock Test Series 1st in English**, RRB NTPC Full Online Mock Test **Series 2nd** in English. RRB Online Test for All Subjects, RRB NTPC Free Mock Test Series in English. RRB NTPC Free Mock Test **Series 2.** RRB NTPC English Language Online Test in English **Series 2nd**. RRB NTPC Quantitative Aptitude Quiz 2018, RRB NTPC Reasoning Ability Free Online Test. Take RRB NTPC Online Quiz. The RRB NTPC Full online mock test paper is free for all students. RRB NTPC Question and Answers in English and Hindi **Series 2**. Here we are providing** RRB NTPC Full Mock Test Paper in English. RRB NTPC **Mock Test **Series 2nd** 2018. Now Test your self for RRB NTPC Exam by using below quiz…

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- Question 1 of 50
##### 1. Question

Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?

CorrectPart filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3

All the three pipes together will fill the tank in 3 hours.IncorrectPart filled by A + B + C in 1 hour = 1/5 + 1/10 + 1/30 = 1/3

All the three pipes together will fill the tank in 3 hours. - Question 2 of 50
##### 2. Question

A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?

Correct40*(40/100) = 16 — 64

? — 12 => Rs.3Incorrect40*(40/100) = 16 — 64

? — 12 => Rs.3 - Question 3 of 50
##### 3. Question

The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?

Correct2C + 3T = 1300 — (1)

3C + 3T = 1200 — (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T – C = 100Incorrect2C + 3T = 1300 — (1)

3C + 3T = 1200 — (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T – C = 100 - Question 4 of 50
##### 4. Question

If 15% of 30% of 50% of a number is 90, then what is the number?

CorrectLet the number be a

Given, 15/100 * 30/100 * 50/100 * a = 90

=> 3/20 * 3/10 * 1/2 * a = 90

=> a = 10 * 20 * 10 * 2 = 4000.IncorrectLet the number be a

Given, 15/100 * 30/100 * 50/100 * a = 90

=> 3/20 * 3/10 * 1/2 * a = 90

=> a = 10 * 20 * 10 * 2 = 4000. - Question 5 of 50
##### 5. Question

A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is?

CorrectLet sum = x. Then, amount = 7x/6

S.I. = 7x/6 – x = x/6; Time = 3 years.

Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %.IncorrectLet sum = x. Then, amount = 7x/6

S.I. = 7x/6 – x = x/6; Time = 3 years.

Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %. - Question 6 of 50
##### 6. Question

15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?

Correct3W = 2M

15M —— 21 * 8 hours

21 W —— x * 6 hours

14 M —— x * 6

15 * 21 * 8 = 14 * x * 6

x = 30Incorrect3W = 2M

15M —— 21 * 8 hours

21 W —— x * 6 hours

14 M —— x * 6

15 * 21 * 8 = 14 * x * 6

x = 30 - Question 7 of 50
##### 7. Question

In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?

CorrectA scores 60 while B score 40 and C scores 30.

The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.

In a game of 100 points, B gives (100 – 75) = 25 points to C.IncorrectA scores 60 while B score 40 and C scores 30.

The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.

In a game of 100 points, B gives (100 – 75) = 25 points to C. - Question 8 of 50
##### 8. Question

A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?

CorrectIncorrect - Question 9 of 50
##### 9. Question

40% of a number is more than 20% of 650 by 190. Find the number?

Correct(40/100) * X – (20/100) * 650 = 190

2/5 X = 320

X = 800Incorrect(40/100) * X – (20/100) * 650 = 190

2/5 X = 320

X = 800 - Question 10 of 50
##### 10. Question

Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?

CorrectLet the present ages of A, B and C be a, b and c respectively.

Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)

(b + c)/2 = 48 => b + c = 96 — (2)

From (1) and (2), we cannot find b.IncorrectLet the present ages of A, B and C be a, b and c respectively.

Given, [(a – 5) + (b – 5)] / 2 = 40 => a + b = 90 — (1)

(b + c)/2 = 48 => b + c = 96 — (2)

From (1) and (2), we cannot find b. - Question 11 of 50
##### 11. Question

In an exam, a candidate secured 504 marks our of the maximum mark of M. If the maximum mark M is converted into 800 marks, he would have secured 384 marks. What is the value of M?

Correct504/M = 384/800

(504 * 800) / 384 = M

M = 1050Incorrect504/M = 384/800

(504 * 800) / 384 = M

M = 1050 - Question 12 of 50
##### 12. Question

Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X’s present age in years?

CorrectLet the present ages of X and Y be 5x and 6x years respectively.

Then, (5x + 7)/(6x + 7) = 6/7

7(5x + 7) = 6(6x + 7) => x = 7

X’s present age = 5x = 35 years.IncorrectLet the present ages of X and Y be 5x and 6x years respectively.

Then, (5x + 7)/(6x + 7) = 6/7

7(5x + 7) = 6(6x + 7) => x = 7

X’s present age = 5x = 35 years. - Question 13 of 50
##### 13. Question

An article was sold after a discount of 20% and there was a gain of 20%. If the profit made on it was Rs. 6 less than the discount offered on it, find its selling price?

CorrectLet CP = Rs. 100x

SP = Rs. 120x

MP = 120x/80 * 100 = Rs. 150x

D = Rs. 150x – Rs. 120x = Rs. 30x

D – P = 30x – 20x = Rs. 6, 10x = Rs. 6

120x = 120/10 * 6 = Rs. 72IncorrectLet CP = Rs. 100x

SP = Rs. 120x

MP = 120x/80 * 100 = Rs. 150x

D = Rs. 150x – Rs. 120x = Rs. 30x

D – P = 30x – 20x = Rs. 6, 10x = Rs. 6

120x = 120/10 * 6 = Rs. 72 - Question 14 of 50
##### 14. Question

Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 2 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them?

CorrectDistance = Relative Speed * Time

= (2 + 3) * 4 = 20 km

[ They are travelling in the opposite direction, relative speed = sum of the speeds].IncorrectDistance = Relative Speed * Time

= (2 + 3) * 4 = 20 km

[ They are travelling in the opposite direction, relative speed = sum of the speeds]. - Question 15 of 50
##### 15. Question

The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?

CorrectTotal members in the group = 7

Average amount = Rs. 20

Total amount with them = 7 * 20 = Rs. 140

One number has Rs. 50. So, the amount with remaining 6 people = 140 – 50 = Rs. 90

The average amount with them = 90/6 = Rs. 15.IncorrectTotal members in the group = 7

Average amount = Rs. 20

Total amount with them = 7 * 20 = Rs. 140

One number has Rs. 50. So, the amount with remaining 6 people = 140 – 50 = Rs. 90

The average amount with them = 90/6 = Rs. 15. - Question 16 of 50
##### 16. Question

Find the one which does not belong to that group ?

CorrectThe digits on either side of the letter in each of the groups 1P6, 2T0, 1M3 and 1R8 indicate the place value of the letter in the alphabet.

This pattern is not followed by 2Y4.IncorrectThe digits on either side of the letter in each of the groups 1P6, 2T0, 1M3 and 1R8 indicate the place value of the letter in the alphabet.

This pattern is not followed by 2Y4. - Question 17 of 50
##### 17. Question

A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 25 m * 2 m * 0.75 m?

Correct25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 = 1/100 * x => x = 25000Incorrect25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 = 1/100 * x => x = 25000 - Question 18 of 50
##### 18. Question

(112 * 5

^{4}) = ?Correct(112 * 5

^{4}) = 112 * (10/2)^{4}

= (112 * 10^{4})/24 = 1120000/16 = 70000Incorrect(112 * 5

^{4}) = 112 * (10/2)^{4}

= (112 * 10^{4})/24 = 1120000/16 = 70000 - Question 19 of 50
##### 19. Question

In what time a sum of money double itself at 3% per annum simple interest?

CorrectP = (P*3*R)/100

R = 33 1/3%IncorrectP = (P*3*R)/100

R = 33 1/3% - Question 20 of 50
##### 20. Question

HCF of 3/16, 5/12, 7/8 is:

CorrectHCF of numerators = 1

LCM of denominators = 48

=> 1/48IncorrectHCF of numerators = 1

LCM of denominators = 48

=> 1/48 - Question 21 of 50
##### 21. Question

A money lender lends Rs.2000 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit.

CorrectA = 2000(21/20)

^{2}= 2205IncorrectA = 2000(21/20)

^{2}= 2205 - Question 22 of 50
##### 22. Question

In a class there are 20 boys and 25 girls. In how many ways can a boy and a girl be selected?

CorrectWe can select one boy from 20 boys in 20 ways.

We select one girl from 25 girls in 25 ways

We select a boy and girl in 20 * 25 ways i.e., = 500 ways.IncorrectWe can select one boy from 20 boys in 20 ways.

We select one girl from 25 girls in 25 ways

We select a boy and girl in 20 * 25 ways i.e., = 500 ways. - Question 23 of 50
##### 23. Question

A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

CorrectHCF of 1189, 1073 = 29

1073/29 = 37IncorrectHCF of 1189, 1073 = 29

1073/29 = 37 - Question 24 of 50
##### 24. Question

A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?

Correct6300:4200:10500

3:2:5

3/10 * 12100 = 3630Incorrect6300:4200:10500

3:2:5

3/10 * 12100 = 3630 - Question 25 of 50
##### 25. Question

If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?

CorrectLet the price of the article be Rs. 100.

20% of 100 = 20.

New price = 100 + 20 = Rs. 120

Required percentage = (120 – 100)/120 * 100

= 20/120 * 100 = 50/3 = 16 2/3%.IncorrectLet the price of the article be Rs. 100.

20% of 100 = 20.

New price = 100 + 20 = Rs. 120

Required percentage = (120 – 100)/120 * 100

= 20/120 * 100 = 50/3 = 16 2/3%. - Question 26 of 50
##### 26. Question

A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?

Correct2420 — 242

100 — ? => 10%Incorrect2420 — 242

100 — ? => 10% - Question 27 of 50
##### 27. Question

A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?

CorrectLength = Speed * time

Speed = L/T

S = 400/20

S = 20 M/Sec

Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)

Speed = 72 KmphIncorrectLength = Speed * time

Speed = L/T

S = 400/20

S = 20 M/Sec

Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)

Speed = 72 Kmph - Question 28 of 50
##### 28. Question

Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?

CorrectWork done by the third pipe in 1 min = 1/50 – (1/60 + 1/75) = – 1/100.

[-ve sign means emptying]

The third pipe alone can empty the cistern in 100 min.IncorrectWork done by the third pipe in 1 min = 1/50 – (1/60 + 1/75) = – 1/100.

[-ve sign means emptying]

The third pipe alone can empty the cistern in 100 min. - Question 29 of 50
##### 29. Question

The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?

Correct2(3x + x) = 96

l = 36 b = 12

lb = 36 * 12 = 432Incorrect2(3x + x) = 96

l = 36 b = 12

lb = 36 * 12 = 432 - Question 30 of 50
##### 30. Question

Kim can do a work in 3 days while David can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Kim?

CorrectKim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3

Kim’s share = 2/5 * 150 = Rs. 60IncorrectKim’s wages : David’s wages = Kim’s 1 day work : David’s 1 day work = 1/3 : 1/2 = 2:3

Kim’s share = 2/5 * 150 = Rs. 60 - Question 31 of 50
##### 31. Question

(56

^{2}– 24^{2}) * 1/32 + ?% of 1200 = 146Correct(56

^{2}– 24^{2}) * 1/32 + ?% of 1200 = 146

=> (3136 – 576) * 1/32 + ?/32 of 1200 = 146

=> 2560/32 + ? * 12 = 146 => ? * 12 = 146 – 80

=> ? = 66/12 => 5 1/2Incorrect(56

^{2}– 24^{2}) * 1/32 + ?% of 1200 = 146

=> (3136 – 576) * 1/32 + ?/32 of 1200 = 146

=> 2560/32 + ? * 12 = 146 => ? * 12 = 146 – 80

=> ? = 66/12 => 5 1/2 - Question 32 of 50
##### 32. Question

Surface area of two spheres are in the ratio 1:4 what is the ratio of their volumes?

CorrectIncorrect - Question 33 of 50
##### 33. Question

The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?

CorrectThe denominator be P, the numerator will be (P – 8).

The fraction will be (P – 8)/P.

Adding 3 to the numerator and subtracting 3 from the denominator, (P – 8 + 3)/(P – 3) = 3/4.

(P – 5)/(P – 3) = 3/4

P = 20 – 9 => P = 11.

The fraction is: 3/11.IncorrectThe denominator be P, the numerator will be (P – 8).

The fraction will be (P – 8)/P.

Adding 3 to the numerator and subtracting 3 from the denominator, (P – 8 + 3)/(P – 3) = 3/4.

(P – 5)/(P – 3) = 3/4

P = 20 – 9 => P = 11.

The fraction is: 3/11. - Question 34 of 50
##### 34. Question

There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?

CorrectW = 62% L = 38%

62% – 38% = 24%

24% ——– 288

62% ——– ? => 744IncorrectW = 62% L = 38%

62% – 38% = 24%

24% ——– 288

62% ——– ? => 744 - Question 35 of 50
##### 35. Question

(49

^{2}* 18^{2}) / 324 = ?Correct(49

^{2}* 324) / 324 = 49^{2}Incorrect(49

^{2}* 324) / 324 = 49^{2} - Question 36 of 50
##### 36. Question

Thirty men can do a work in 24 days. In how many days can 20 men can do the work, given that the time spent per day is increased by one-third of the previous time?

CorrectLet the number of hours working per day initially be x. we have M

_{1}D_{1}H_{1}= M_{2}D_{2}H_{2}

30 * 24 * x = 20 * d_{2}* (4x)/3 => d_{2}= (30 * 24 * 3)/(24 * 4) = 27 days.IncorrectLet the number of hours working per day initially be x. we have M

_{1}D_{1}H_{1}= M_{2}D_{2}H_{2}

30 * 24 * x = 20 * d_{2}* (4x)/3 => d_{2}= (30 * 24 * 3)/(24 * 4) = 27 days. - Question 37 of 50
##### 37. Question

60% of a number is added to 120, the result is the same number. Find the number?

Correct(60/100) * X + 120 = X

2X = 600

X = 300Incorrect(60/100) * X + 120 = X

2X = 600

X = 300 - Question 38 of 50
##### 38. Question

Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?

CorrectLCM = 300/60 = 5 min

IncorrectLCM = 300/60 = 5 min

- Question 39 of 50
##### 39. Question

A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?

Correct5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 daysIncorrect5/30 + 20/x = 1

x = 24

1/30 + 1/24 = 3/40

40/3 = 13 1/3 days - Question 40 of 50
##### 40. Question

If 5 men and 2 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?

Correct5M + 2B = 4(1M + 1B)

5M + 2B = 4M + 4B

1M = 2B

The required ratio of work done by a man and a boy = 2:1Incorrect5M + 2B = 4(1M + 1B)

5M + 2B = 4M + 4B

1M = 2B

The required ratio of work done by a man and a boy = 2:1 - Question 41 of 50
##### 41. Question

³√216400 + √280 + √322 = ?

Correct³√216400 + √280 + √322

= 60 + 16.5 + 18 = 94.5 = 95Incorrect³√216400 + √280 + √322

= 60 + 16.5 + 18 = 94.5 = 95 - Question 42 of 50
##### 42. Question

Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?

CorrectLet the speed of the slower train be x m/sec.

Then, speed of the train = 2x m/sec.

Relative speed = ( x + 2x) = 3x m/sec.

(100 + 100)/8 = 3x => x = 25/3.

So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr.IncorrectLet the speed of the slower train be x m/sec.

Then, speed of the train = 2x m/sec.

Relative speed = ( x + 2x) = 3x m/sec.

(100 + 100)/8 = 3x => x = 25/3.

So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr. - Question 43 of 50
##### 43. Question

Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?

CorrectT = (121 + 165)/ (80 + 65) * 18/5

T = 7.15IncorrectT = (121 + 165)/ (80 + 65) * 18/5

T = 7.15 - Question 44 of 50
##### 44. Question

I. a

^{2}– 7a + 12 = 0,

II. b^{2}– 3b + 2 = 0 to solve both the equations to find the values of a and b?CorrectI.(a – 3)(a – 4) = 0

=> a = 3, 4

II. (b – 2)(b – 1) = 0

=> b = 1, 2

=> a > bIncorrectI.(a – 3)(a – 4) = 0

=> a = 3, 4

II. (b – 2)(b – 1) = 0

=> b = 1, 2

=> a > b - Question 45 of 50
##### 45. Question

Find the number of ways of arranging the letters of the word “MATERIAL” such that all the vowels in the word are to come together?

CorrectIn the word, “MATERIAL” there are three vowels A, I, E.

If all the vowels are together, the arrangement is MTRL’AAEI’.

Consider AAEI as one unit. The arrangement is as follows.

M T R L**A A E I**

The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.

Number of required ways of arranging the above letters = 5! * 4!/2!

= (120 * 24)/2 = 1440 ways.IncorrectIn the word, “MATERIAL” there are three vowels A, I, E.

If all the vowels are together, the arrangement is MTRL’AAEI’.

Consider AAEI as one unit. The arrangement is as follows.

M T R L**A A E I**

The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.

Number of required ways of arranging the above letters = 5! * 4!/2!

= (120 * 24)/2 = 1440 ways. - Question 46 of 50
##### 46. Question

All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?

CorrectB has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.

Quantity of water in B = 8k – 5k = 3k.

Quantity of water in container C = 8k – 3k = 5k

Container: A B C

Quantity of water: 8k 3k 5k

It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.

5k – 148 = 3k + 148 => 2k = 296 => k = 148

The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.IncorrectB has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.

Quantity of water in B = 8k – 5k = 3k.

Quantity of water in container C = 8k – 3k = 5k

Container: A B C

Quantity of water: 8k 3k 5k

It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.

5k – 148 = 3k + 148 => 2k = 296 => k = 148

The initial quantity of water in A = 8k = 8 * 148 = 1184 liters. - Question 47 of 50
##### 47. Question

The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?

CorrectArea of the four walls = 2h(l + b)

Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) – (6 * 3) – 3(4 * 3) = 906 sq.ft.

Total cost = 906 * 5 = Rs. 4530IncorrectArea of the four walls = 2h(l + b)

Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) – (6 * 3) – 3(4 * 3) = 906 sq.ft.

Total cost = 906 * 5 = Rs. 4530 - Question 48 of 50
##### 48. Question

If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:

CorrectLet C.P. of each pen be Re. 1.

Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.

Gain % = 4/8 * 100 = 50%IncorrectLet C.P. of each pen be Re. 1.

Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.

Gain % = 4/8 * 100 = 50% - Question 49 of 50
##### 49. Question

A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?

Correct10 * 150 = 1500

3 * 100 + 5 * 150 = 1050

1500 – 1050 = 450Incorrect10 * 150 = 1500

3 * 100 + 5 * 150 = 1050

1500 – 1050 = 450 - Question 50 of 50
##### 50. Question

If 35% of a number is 12 less than 50% of that number, then the number is?

CorrectLet the number be x. Then,

50% of x – 35% of x = 12

50/100 x – 35/100 x = 12

x = (12 * 100)/15 = 80.IncorrectLet the number be x. Then,

50% of x – 35% of x = 12

50/100 x – 35/100 x = 12

x = (12 * 100)/15 = 80.